Find the area of quadrilateral
ABCD whose sides are 9m,40m,28m and 15m.
and is The angle betweend the first two sides is a right angle........by heron's formula
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Answer:
126m²
Step-by-step explanation:
The area of a quadrilateral
solution
In ∆ABC
AB ,=9m,BC=40m
- LABC=90°
Area of ∆ABC=½×B×H
=½×AB×BC
=½×9cm×40
=180m²
Area of ABC=÷8(8-a) (8-b) (8-c)m²
=÷42(42-1) (42-28)-(42-8)
= ÷42×27×14×1²
= 126m²
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