Question

find the area of quadrilateral abcd whose vertices are A (-3,9) B (-2,3) C(1,-4) D(6,7)

Answer 1

Answer:

Area triangle ABC =(-3(3+4)+(-2)(-4-9)+(1)(9-3))

                              =(-21+26+6)

                              =11 sq units

Area Triangle ADC=(-3(-4-7)+1(7-9)+6(9+4)

                               =109sq units

Total area=120sq units

Step-by-step explanation: