Question

find the area of quadrilateral
answer:72

Answer 1

$<h2 > hey there$

$<h4 > answer$

Area of triangle ABD

⊙$<i > refer the yellow paper$

Area of triangle DBC

⊙$<b > refer to the pink paper$

So, area = 59+15= 74 sq units

Hope it helps you

$<marquee > prabhudutt$

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Answer 2

Answer:

72 sq.units

Step-by-step explanation:

Given Vertices are A(-5,7), B(-4,-5), C(-1,-6), D(4,5)

(i) Area of ΔABD:

⇒ (1/2)|x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)|

⇒ (1/2)|(-5)(-5 - 5) + (-4)(5 - 7) + (4)(7 + 5)|

⇒ (1/2)|50 + 8 + 48|

⇒ 106/2

⇒ 53 sq.units

(ii) Area of ΔBCD:

⇒ (1/2)|x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)|

⇒ (1/2)|(-4)(-6 - 5) + (-1)(5 + 5) + (4)(-5 + 6)|

⇒ (1/2)|44 - 10 + 4|

⇒ (1/2)|38|

⇒ 19 sq.units

Therefore, Area of quadrilateral ABCD = 53 + 19

                                                                 = 72 sq.units.

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