find the area of quadrilateral whose 180 diagonal is 12 cm long and the length of the perpendiculars on it from opposite vertices are 4cm and 5cm
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Area= 54cm^2
Explaination:
Given three integers d, h1, h2 where d represents the length of the diagonal of a quadrilateral. h1 and h2 represents the lengths of the perpendiculars to the given diagonal from the opposite vertices. The task is to find the area of the Quadrilateral.
Area of the quadrilateral is the sum of the areas of both triangles. We know that the area of the triangle is 1/2*base*height.
Therefore, the area of a quadrilateral can be calculated as :
Area = 1/2 * d * h1 + 1/2 * d * h2
= 1/2 * d * ( h1 + h2 )
Using this,
Area = 1/2 × 12 (4 + 5 ) = 6 × 9 = 54 cm^2.
It's simple :-))
HOPE IT HELPS..
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