Question

Find the area of quadrilateral whose heights are 2.4 cm and

3.1 cm and the diagonal is 5cm.​

Answer 1

Answer:

Step-by-step explanation:

BC=10cm

h  

1

​  

=5cm,h  

2

​  

=7cm

Area of Quadrilateral=area $$(\triangle ABC)+area (△BCD)

=  

2

1

​  

×BC×h  

1

​  

+  

2

1

​  

×BC×h  

2

​  

 

=(  

2

1

​  

×10×5+  

2

1

​  

×10×7)cm  

2

 

=(25+35)cm  

2

=60cm  

2

Answer 2

Answer:

Step-by-step explanation:

Given

Height 1= 2.4 cm = parellel side 1

Height 2= 3.1 cm = parellel side 2

Diagonal = 5 cm = height

Area of genral quadilateral = 1/2 * height * (Sum of parallel sides)

                                              = 1/2 * 5 cm * (2.4 cm + 3.1 cm)

                                               = 1/2 * 5cm * 5cm

                                               = 1/2 * 25 cm

                                               = 12.5 cm^2

Therefore the area will be 12.5 cm^