Question

Find the area of quadrilateral whose lengths of diagonal is 12 cm and length of perpendiculars drawn from opposite vertices to the diagonal are 7 cm and 8 cm respectively

Answer 1

Heyaa....☺☺✌

In quad. ABCD
AC = 12 cm
DL = 8 cm
BM = 7 cm

Now in triangle ADC
Base = AC = 12
Height = DL = 8

Area = 1/2 ×b ×h
=> 1/2 × 12 × 8
=> 48 Sq cm

Again in triangle ABC
Base = AC = 12
Height = BM = 7

Area = 1/2 × b × h
=> 1/2 × 12 × 7
=> 42 Sq cm

Now total area of quad ABCD = Area of triangle ADC + Area of triangle ABC
=>( 48 + 42 ) Sq cm
=> 90 Sq cm

Hope it helps uh...

Thanks...☺☺✌

Answer 2

Answer:

Step-by-step explanation:

Heyaa....☺☺✌

In quad. ABCD

AC = 12 cm

DL = 8 cm

BM = 7 cm

Now in triangle ADC

Base = AC = 12

Height = DL = 8

Area = 1/2 ×b ×h

=> 1/2 × 12 × 8

=> 48 Sq cm

Again in triangle ABC

Base = AC = 12

Height = BM = 7

Area = 1/2 × b × h

=> 1/2 × 12 × 7

=> 42 Sq cm

Now total area of quad ABCD = Area of triangle ADC + Area of triangle ABC

=>( 48 + 42 ) Sq cm

=> 90 Sq cm

Hope it helps uh...

Thanks...☺☺✌