Question

find the area of quadrilateral whose one diagonal is 20 cm long and the perpendicular to this diagonal from other vertex are of length 9 cm and 15 CM

Answer 1

Considering Triangle ABC
Area of ABC = 1/2 * BC * AE = 1/2 * 20 * 9 = 90cm²

Again in triangle DBC
Area of DBC = 1/2 * BC * DF = 1/2 * 20 * 15 = 150cm²

Now,
Area of quadrilateral ABCD =
$area \: of \: abc + area \: of \: dbc$
So,
Area of ABCD = 90 + 150 = 240cm²

Hope this will be helping you

WARM REGARDS
Sahil khirwal

Answer 2

Answer:

Given ABCD is a quadrilateral with AC=20cm and BP=9cm & OD=15cm and BP⊥AC & OD⊥AC

area of ΔABC=

2

1

×AC×BP=

2

1

×20×9=90cm

2

[Area of ΔABC−90cm

2

]

Area of ΔADC=

2

1

×AC×OD=

2

1

×20×15=150cm

2

Area of [ΔADC=150cm

2

]

Area of quadrilateral =area of ΔADC+ area of Δ ABC

=90+150

Area of quadrilateral (ABCD)=240cm

2

Hence area of quadrilateral ABCD is 240cm

2

.