Question

find the area of quadrilateral whose sides are 9 CM 40 cm 28 cm and 15 CM the angel between the first two sides of the quilateral is a right angle​

Answer 1

Answer:

306 sq.cm

Step-by-step explanation:

we divide the quadrilateral in two triangle ,one becomes right triangle as it's one angle is 90° and triangle is scalene in nature.

To find area of right triangle

area of triangle=1/2×base ×height

=1/2×9 ×40

=180sq.cm

To find area of scalene triangle:

first we need to find length of one of its diagonal through which we divide the quadrilateral in two triangles.

for this using Pythagoras theorem in right triangle,we get length of diagonal =41cm

now ,area of triangle can be found by using Heron's formula

A=√s(s-a)(s-b)(s-c)

here ,s is semi perimeter

and, s=(a+b+c)/2

=(15+28+41)/2

=42cm

again, area A=√(42-15)(42-28) (42-41)

=306sq.cm