Question

find the area of quadrilateral whose vertices are( 2,1)(6,0)(5, - 2) and (-3 - 1)​

Answer 1

Heya,

According to the question,

Coordinates of the quadrilateral are;

A(5,-2) = (x1, y1)

B(-3,-1) = (x2, y2)

C(2,1) = (x3, y3)

D(6,0) = (x4, y4)

To find area of quadrilateral we will use the formula,

Area of quadrilateral ABCD = 1/2| (x1 - x3)(y2 - y4) - (y1 - y3)(x2 - x4) |

= 1/2 | (5 - 2)(-1 - 0) - (-2 - 1)(-3 - 6) |

= 1/2 | 3×(-1) - (-3)×(-9) |

= 1/2 | -3 - 27 |

= 1/2 × 30

= 15 unit². ..... Answer

Hope this helps....:)

Answer 2

Answer:

Hope it will help you

Step-by-step explanation:

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