Question

Find the area of quadrilateral whose vertices are A(0,-4),B(4,0),C(-4,0),D(0,4)​

Answer 1

Answer:

area of quadrilateral = 32 sq units

Step-by-step explanation:

area of quadrilateral  ABCD

= Area of Triangle ABC   + Area of Triangle ACD

A(0,-4),B(4,0),C(-4,0)

Area of Triangle ABC  = (1/2) | 0 (0 - 0 )  + 4 (0 -(-4)) + (-4)(-4 - 0)|

= (1/2) | 0 + 16 + 16|

= 32/2

= 16

A(0,-4),C(-4,0),D(0,4)​

Area of Triangle ACD = (1/2) | 0 (0 - 4 )  - 4 (4 -(-4)) + 0(-4 - 0)|

= (1/2) | - 32|

= 32/2

= 16

area of quadrilateral = 16 + 16 = 32 sq units