Find the area of Quadrilateral whose vertices, taken in order are
(-4,-2), (-3,-5), (3,-2), (2,3)
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Step-by-step explanation:
let A =( -4 , -2) B = (-3 , -5) C= (3,-2) D = (2,3)
now in triangle ABD
area = 1/2 { 2*(-2 + 5) - 4(-5 -3)-3(3 + 2)}
1/2 { 2*3 4* (-8) 3 * 5 )
1/2{ 6 + 32 - 15}
23/2
therefore area of triangle ABD = 23/2 unit -1 square now area of triangle BCD area = 1/2{ -3(-2 -3) + 3(3 + 5) + 2(-5 +2)}
1/2 {-3 * -5 + 3 * 8 + 2 * (- 3)}
1/2 {15 + 24 - 6}
33/2
therefore area of triangle BCD = 33/2 unit square--------- 2
adding 1 & 2
23/2 + 33/2
( 23 + 33 )/2
56 / 2
28
therefore totall area = 28 unit square
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