Question

Find the area of Quadrilateral whose vertices, taken in order are

(-4,-2), (-3,-5), (3,-2), (2,3)​

Answer 1

Step-by-step explanation:

let A =( -4 , -2) B = (-3 , -5) C= (3,-2) D = (2,3)

now in triangle ABD

area = 1/2 { 2*(-2 + 5) - 4(-5 -3)-3(3 + 2)}

1/2 { 2*3 4* (-8) 3 * 5 )

1/2{ 6 + 32 - 15}

23/2

therefore area of triangle ABD = 23/2 unit -1 square now area of triangle BCD area = 1/2{ -3(-2 -3) + 3(3 + 5) + 2(-5 +2)}

1/2 {-3 * -5 + 3 * 8 + 2 * (- 3)}

1/2 {15 + 24 - 6}

33/2

therefore area of triangle BCD = 33/2 unit square--------- 2

adding 1 & 2

23/2 + 33/2

( 23 + 33 )/2

56 / 2

28

therefore totall area = 28 unit square