Question

find the area of quadrilaterals in the adjoining figures ​

Answer 1

Answer :

The area of quadrilaterals is 21 cm²

Given:

Side = 4 cm

Diagonal,

$d_{1} = 7 cm\\d_{2} = 6 cm$

To find:

Area of quadrilaterals

Explanation:

Area of quadrilaterals =

$=\frac{1}{2} \times d_{1} \times d_{2} \\=\frac{1}{2} \times 7 \times 6 \\= 21 cm^{2}$

Quadrilateral :

The polygon with four sides, four angles, and four vertices is called the quadrilateral. The sum of the interior angles of a quadrilateral is always equal to 360 degrees. Geometric shapes having a definite shape and properties made up of lines, curves and points. Some of the geometric shapes are square, rectangle, circle, cone, cylinder, sphere, etc. There are various types of quadrilaterals – Rectangle, Square, Parallelogram, Trapezium or Trapezoid, and Rhombus. A rhombus is a quadrilateral with four equal sides. It has diagonals that bisect each other.

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Answer 2

Answer:

The area of quadrilaterals is 21 cm²

Given:

Side = 4 cm

Diagonal,

�

1

=

7

�

�

�

2

=

6

�

�

d

1

=7cm

d

2

=6cm

To find:

Area of quadrilaterals

Explanation:

Area of quadrilaterals =

=

1

2

×

�

1

×

�

2

=

1

2

×

7

×

6

=

21

�

�

2

=

2

1

×d

1

×d

2

=

2

1

×7×6

=21cm

2