Question

Find the area of quadrilatral abcd the coordinate of whose vertices are a(1,2) b(6,2) c(5,3) and d(3,4)

Answer 1

Let us divide the quadrilateral ABCD is divided into two triangles ABD and BCD.

Area of quadrilateral ABCD = Area of triangle ABD + Area of triangle BCD

Area of triangle with coordinates is given by the formula:



Area of triangle ABD with coordinates A(1,2) B(6,2) and D(3,4)

Area of triangle ABD =

Area of triangle ABD =

= square units.

Area of triangle BCD with coordinates B(6,2) C(5,3) D(3,4)

Area of triangle BCD =

=

= 0.5 square units.

Area of quadrilateral ABCD = Area of triangle ABD + Area of triangle BCD

= 5 + 0.5

= 5.5 square units.

Therefore, the area of the given quadrilateral ABCD is 5.5 square units.

,

Answer 2

$\textbf{Answer}$

= 5.5 square unit

$\textbf{look in attachment}$

Method=>

Vector calculas

=By vector calculas