Question

find the area of rectangle, length=12m breadth=10m with explanation.​

Answer 1

Answer:

Area is =120$cm^{2}$

Step-by-step explanation:

According to the information provided in the question  it is given as

Length = l =12cm

Breadth =b =10cm

We need to find the area of rectangle

For solving this first understand the rectangle rectangle is the shape in which two sides are equal called as length and two side are equal called breadth the length is greater in size as compared to breadth

There is a formula for finding the area of rectangle

Area = Length x Breadth

By putting the values we get the area

$A= 12\times 10\\A= 120cm^{2}$

Hence the area is =120$cm^{2}$

Answer 2

Question :-

• Find the Area of Rectangle, if Length is 12 meter and Breadth is 10 meter.

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Answer :-

• Area of Rectangle is 120 m² .

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Explanation :-

• Here, Lenght of Rectangle is given 12 meter . Breadth is 10 meter . And, we have to calculate the Area of Rectangle .

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➻ Formula Required :-

• $\sf {Area \: of \: Rectangle = Lenght \times Breadth}$

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➻ By substituting given values :-

$\Longrightarrow \: \sf{Area \: of \: Rectangle = 12 \times 10}$

$\Longrightarrow \: \sf{Area \: of \: Rectangle = 120 \: m^{2} }$

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Hence :-

• Area = 120 m² .

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$\begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \pmb {\sf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Square = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \sf{Area \: of \: Rectangle = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Triangle = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Parallelogram = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Trapezium = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \sf {Area \: of \: Rhombus = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered}$