find the area of rectangle plot one side of which is 48mtrs and its diagonal 50mtrs
Answers
Answered by
1
by pythagoras theorem,
50^2 = 48^2 + other side^2
2500 = 2304 +other side^2
2500-2304 = other side^2
196 = other side^2
14= other side
Now,
area of rectangle = length *breadth
area of rectangle = 14*48
area of rectangle = 672m^2
i hope this will help you
-by ABHAY
50^2 = 48^2 + other side^2
2500 = 2304 +other side^2
2500-2304 = other side^2
196 = other side^2
14= other side
Now,
area of rectangle = length *breadth
area of rectangle = 14*48
area of rectangle = 672m^2
i hope this will help you
-by ABHAY
Answered by
0
Hey!
______________________
Length of one side (width) = 48 m
Length of diagonal = 50 m
Length of another side (length)=?
Using Pythagoras Theorem - :
H^2 = B^2 + P^2
50^2 = B^2 + 48^2
2500 = B^2 + 2304
2500-2304= B^2
196 = B^2
B = √196
B= 14 m
Thus, length = 14 m
Area = Length × Breath
Area = 14×48
Area = 672 m^2
______________________
Hope it helps...!!!
______________________
Length of one side (width) = 48 m
Length of diagonal = 50 m
Length of another side (length)=?
Using Pythagoras Theorem - :
H^2 = B^2 + P^2
50^2 = B^2 + 48^2
2500 = B^2 + 2304
2500-2304= B^2
196 = B^2
B = √196
B= 14 m
Thus, length = 14 m
Area = Length × Breath
Area = 14×48
Area = 672 m^2
______________________
Hope it helps...!!!
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