Question

Find the area of rectangle this length is 26 cm and breadth is 10 cm .

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Answer 1

Answer:

lenth=26cm

breath=10cm

area=lxb

26x10=260cm^2

Answer 2

Correct Question-:

• Find the area of rectangle whose length is 26 cm and breadth is 10 cm .

AnswEr-:

• $\underline{\boxed{\star{\sf{\blue{ Area \: of\: Rectangle\:= \:260cm² }}}}}$

Explanation-:

Given -:

• The Length of Rectangle is 26 cm .
• The breadth of Rectangle is 10 cm .

☆ Figure related to the question-:

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large x cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large y cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

To Find -:

• The area of Rectangle.

Solution-:

• $\underline{\boxed{\star{\sf{\blue{ Area\:of\:Rectangle\:= \:Length \times Breadth }}}}}$

Here ,

• The Length of Rectangle is 26 cm .
• The breadth of Rectangle is 10 cm .

Now ,

• $\implies{\sf{\large {Area_{Rectangle}= 26 \times 10 }}}$
• $\implies{\sf{\large {Area_{Rectangle}= 260cm² }}}$

Therefore,

• $\underline{\boxed{\star{\sf{\blue{ Area_{Rectangle}\:= \:260cm² }}}}}$

Hence ,

• $\underline{\boxed{\star{\sf{\blue{ Area \: of\: Rectangle\:= \:260cm² }}}}}$

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