find the area of rectangle through a rectangular whose whose parameter is perimeter is 180 metre and breadth is 40
Answers
Answered by
0
Firstly we find length
so,
perim. of rectangle=2×(l+b)
180 =2×(l+40)
180/2=l+40
90=l+40
90-40=l
50=length
therefore,
area of rectangle=l×b
50×40
2000sq.m
so,
perim. of rectangle=2×(l+b)
180 =2×(l+40)
180/2=l+40
90=l+40
90-40=l
50=length
therefore,
area of rectangle=l×b
50×40
2000sq.m
Answered by
1
Answer
Area of Rectangle=L*B
Perimetre=2(l+b)
180=2(l+40)
180=2l+80
2l=180-80=100
2l=100
l=100/2
=50
l=50 b=40
So area of the rectangle with perimetre 180 and breadth 40 is
l*b
50*40=2000cm^2
Step-by-step explanation:
HOPE U UNDERSTAND THE WAY.
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