Question

. Find the area of rectangle which length is 48 m find the area of rectangle and diagonal 50m.​

Answer 1

Answer:

672m²

Explanation:

In a rectangle,

• Length = 48m
• Diagonal = 50m

Find it's area.

We know that,

Area of a rectangle = $l \ast b$

Where,

• $l$ denotes the length.
• $b$ is the breadth.

Lets find $\boldsymbol b$

Recall the property of a rectangle, which is each interior angle of a rectangle is 90°.

So we can apply the Pythagoras theorem to find the breadth.

Here,

length would be base diagonal would be hypotenuse.

By Pythagoras theorem,

→ (d)² = (l)² + (b)²

→ (50)² = (48)² + b²

→ 2500 = 2304 + b²

→ 2500 - 2304 = b²

→ 196 = b²

→ √196 = b²

→ b = 14

So the breadth is 14m.

Hence, area of the rectangle:-

$=l \ast b$

$= 48 \ast 14$

$\rm = 672m^2$

Required answer: 672m²