find the area of rectangle whose breadth is 8cm and length of one of its diagnol is 17
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Answer: 120 cm²
Let the rectangle be named as ABCD,
Now the length of the breadth is given as 8 cm.
Since, we know that a rectangle has parallel sides, hence they make 90° with each other.
The diagonal is of length 17 cm.
Hence we obtain a triangle ABC with the 90° at B.
Therefore, using Pythagoras theorem, we can find the missing side BC (i.e. the length) :
(AB)² + (BC)² = (AC)²
(AC)² - (AB)² = (BC)²
(17)² - (8)² = (BC)²
289 - 64 = (BC)²
225 = (BC)²
∴ BC = 15 cm
Hence Area of the rectangle is given by L×B
= 15 × 8
= 120 cm
Answered by
0
Answer:
120cm²
Step-by-step explanation:
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