Question

find the area of rectangle whose breath is 7m and it's perimeter is equal to that of square with side 12m​

Answer 1

Step-by-step explanation:

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Answer 2

Correct Question:-

Find the area of rectangle whose breath is 7m and it's perimeter is equal to that of square with side 12m.

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Answer:-

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Given:

▪︎Perimeter of rectangle = Perimeter of square

▪︎Side of square = 12m

▪︎Breadth of rectangle = 7m

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To Find:

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▪︎Area of rectangle

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Solution:

According to given conditions;

$\boxed{\bf{Perimeter\ of\ rectangle = Perimeter\ of\ square}}$

${\bf{\implies2(length+breadth) = 4 × side}}$

${\bf{\implies2(length + 7) = 4 × 12}}$

${\bf{\implies length + 7 = 48 ÷ 2}}$

${\bf{\implies length = 24 - 7}}$

Hence, length = 17m

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${\bf{Area\ of\ rectangle}}$

${\bf{= length × breadth}}$

${\bf{= 17 × 7}}$

${\bf{= 119 m²}}$

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Formula to be remembered:-

▪︎Perimeter of rectangle = 2(length + breadth)

▪︎Perimeter of square = 4 × side

▪︎Perimeter of triangle = Sum of all sides

▪︎Area of rectangle = length × breadth

▪︎Area of square = Side²

▪︎Area of triangle = ½ × base × height

Or by Heron's Formula