Question

find the area of rectangle whose length & breadth ar respectively (4x²-3x+7)& (3-2x+3x²)​

Answer 1

Answer:

$12x^4-17x^3+39x^2-23x+21$ is the area of the rectangle.

Step-by-step explanation:

The length of the rectangle is $4x^2-3x+7$

The breadth of the rectangle is $3-2x+3x^2=3x^2-2x+3$

The area of a rectangle can be found out by multiplying length with breadth.

Therefore, $A=l*b$

That is, $A=(4x^2-3x+7)(3x^2-2x+3)$

$=4x^2(3x^2-2x+3)-3x(3x^2-2x+3)+7(3x^2-2x+3)$

$=12x^4-8x^3+12x^2-9x^3+6x^2-9x+21x^2-14x+21$

$=12x^4-17x^3+39x^2-23x+21$

Hope it helps.