Math, asked by kr10092009, 2 months ago

Find the area of rectangle whose length and breadth are 15 cm and 9 cm.​

Answers

Answered by simran7539
22

Solution

Given :-

  • The length of the rectangle is 15 cm.

  • The breadth of the rectangle is 9 cm.

To Find :-

  • The area of the rectangle.

Step-by-Step-Explaination :-

As we know that :-

Area of rectangle = Length × Breadth

Where,

  • The length of the rectangle = 15 cm.

  • The breadth of the rectangle = 9 cm.

Putting the respective value,

Area of rectangle = 15 × 9

Area of rectangle = 135

Hence,

The area of rectangle is 135 cm².

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Know More :-

Perimeter of Rectangle = 2( L + B )

Perimeter of square = 4 × Side

Perimeter of triangle = AB + BC + CA

Area of Rectangle = L × B

Area of Square = ( side ) ²

Area of Rhombus = Product of Diagonal/2.

Area of Parallelogram = Base × Height.

Area of triangle = 1/2 × base × height .

______________________________

Answered by Choudharipawan123456
2

Answer:

The area of a rectangle is 135cm^2.

Step-by-step explanation:

As per the data given in the above question,

Given that:-

The length of a rectangle = 15cm

The breadth of a rectangle = 9cm

We have to find the area of a rectangle,

The area of a rectangle is calculated by multiplying the length and breadth of a rectangle.

Here we have to use the formula of the area of a rectangle,

i.e., A = l\times b$

Where, l = length  

            b = breadth

Given:- l = 15cm and b = 9cm

Substitute the given values of length and breadth in the above formula we get,

A = 15\times 9

Multiplying 15 by 9, we get

A = 135cm^2

Hence, the required solution is 135cm^2.

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