Find the area of rectangle whose length and breadth are 16y2m and 13ymn respectively.
Answers
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Given :- Find the area of rectangle whose length and breadth are 16y²m and 13ymn respectively. ?
Solution :-
given that,
→ Length of rectangle is = 16y²m .
→ Breadth of rectangle is = 13ymn .
we know that,
- Area of rectangle = Length * Breadth .
So,
→ Area of rectangle = L * B
→ Area of rectangle = (16y²m) * (13ymn)
taking like terms together,
→ Area of rectangle = (16 * 13) * (y² * y) * (m * m) * n
using a^m * a^n = (a)^(m + n)
→ Area of rectangle = 208 * {(y)^(2 +1)} * {(m)^(1+1)} * n
→ Area of rectangle = 208 * y³ * m² * n
→ Area of rectangle = (208y³m²n) unit² (Ans.)
Hence, Area of given rectangle is (208y³m²n) unit² .
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