Question

find the area of rectangle whose length and breadth in units are as given as 3x³y² and (x²y⁵)/6​

Answer 1

Answer:

$\frac{x^5y^7}{2}$

Step-by-step explanation:

Given:

l = 3x³y²

b = (x²y⁵)/6​

To find:

Area of the rectangle.

We know, area of rectangle = lb

= $(3x^2y^2)(\frac{x^2y^5}{6})\\\\(x^3y^2)(\frac{x^2y^5}{2})\\\\=\frac{x^5y^7}{2}$