Question

Find the area of rectangle whose length is 40 cm and diagonal is 41 cam

Answer 1

Answer:

Step-by-step explanation:

A=360cm²

l Length  

40

cm

d Diagonal  

41

cm

Answer 2

Given:-

• Diagonal of the rectangle is 41 cm
• Length of rectangle is 40 cm.

To Find:-

• Area of rectangle?

Solution:-

Breadth of rectangle:-

$\dag{ \boxed{ \underline{ \tt { \pink{hypotenuse² = length² + breadth²}}}}}$

$\Longrightarrow {41}^{2} = {40}^{2} + {b}^{2} \\ \\ \Longrightarrow 1681 = 1600 + {b}^{2} \\ \\ \Longrightarrow1681 - 1600 = {b}^{2} \\ \\ \Longrightarrow81 = {b}^{2} \\ \\ \Longrightarrow \sqrt{81} = b \\ \\ \Longrightarrow \dag{ \boxed{ \underline{ \tt{ \green{b = 9}}}}}$

Area of rectangle:-

$\dag{ \boxed{ \underline{ \tt{ \blue{length \times breadth}}}}}$

$\Longrightarrow40 \times 9 \\ \\ \Longrightarrow \dag{ \boxed { \underline{ \tt{ \red{{360 \: cm}^{2} }}}}}$

Hence, the area of rectangle is 360 cm².