find the area of rectangle whose length is 5 more than double its width and perimeter is 247 cm
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Answer:
3318 sq cm
Step-by-step explanation:
let breadth of the rectangle= a cm
length of the rectangle= 2a+5 cm
perimeter= 2(l+b)= 247 cm
= > 2(2a+5+a)= 247
=>2(3a+5) = 247
=>6a+10= 247
=> 6a= 247-10
a= 237/6
a= 39.5
breadth= a= 39.5 cm
length = 2a+5= 2×39.5 +5= 84 cm
area of rectangle= l× b
= 39.5× 84
= 3318 sq cm
3318 sq cmso, area of rectangle= 3318 sq cm
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