Math, asked by deepaksaw757, 1 year ago

Find the area of rectangle whose length is twice the breadth and perimeter is 30 cm

Answers

Answered by sachinthakur17p7iyua
52

Answer:


Step-by-step explanation:


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Answered by aakashshaw305
0

Answer:

The area of rectangle is 50 cm².

Explanation:

Let the breadth of the rectangle = x cm.

Length of the rectangle = 2x cm

Perimeter = 30 cm

2(length + breadth) = 30

2(2x + x) = 30\\2(3x) = 30\\6x = 30\\x = \frac{30}{6} \\x = 5

So, breadth = 5 cm

Therefore, length = 2× breadth

= 2×5 = 10 cm

Area of the rectangle = length ×breadth

= 10×5

= 50 cm²

Hence, the area of rectangle is 50 cm².

Area :

The area occupied by a two-dimensional figure is its surface area. In other words, it is the quantity that determines how many unit squares are present on the surface of a closed figure. Area is typically measured in square units like square inches, square feet, etc. It is used to compute the area encircled by different geometric figures. A cone is a circular, three-dimensional shape. This suggests that the base is composed of a radius. The height of the cone is determined by measuring the distance between the base's centre and its highest point.

To learn more about area visit:

https://brainly.in/question/14759304

https://brainly.in/question/33830840

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