Question

Find the area of rectangle whose perimeter is 160 m and length is 30 m​

Answer 1

Answer:

b=20

Step-by-step explanation:

given

length=30

perimeter=160

We know that

perimeter of rectangle:-2(l+b)

2(l+b)=160

l+b=80

30+b=80

b=50

We know that

area of rectangle:-l×b

30×50=1500

hence area of rectangle=1500

Answer 2

Required Answer :

Area of rectangle = 1500m²

Step by step explanation :-

Given :

. Perimeter of rectangle = 160m

. Length of rectangle = 30m

To find :

. Breadth of rectangle

. Area of rectangle

Formula of perimeter nd Area of rectangle:

$Area \: of \: rectangle \: = 2(l +b ) \\ \\ \\ Perimeter \: of \: rectangle = \: l \times b$

Explanation :

Let the breadth of rectangle is = b

Now,

using the formula of perimeter of rectangle=

perimeter of rectangle = 2(l+b)

160 = 2(30 + b)

=>160 = 60 + 2b

=> 2b = 160 - 60

=> 2b = 100m

=> b = 100/2

=> b = 50m

so,

Breadth of rectangle = 50 m

HENCE,

We have length of rectangle = 30m

nd, breadth of rectangle = 50m

Hence,

We will find the Area of rectangle by using formula as :

Area of rectangle = l × b

Area of rectangle = 30× 50

Area of rectangle = 1500m²

so, the Area of rectangle = 1500m²