find the area of rectangle whose perimeter is 40 cm and breadth 5 cm
Answers
Step-by-step explanation:
Given,perimeter =40 cm
breadthe 'b' = 5 cm
Let length be l cm
So, 2(l+b) = 40cm
2(l+5) = 40cm
l+5= 20cm
l= 15cm
Now , area= l×b
So, Area= 15cm×5cm
Area= 75 cm^2
Answer:
Step-by-step explanation:
Given,
Perimeter of rectangle = 40 cm
Breadth of rectangle = 5 cm
Length of rectangle = ? (To be Calculated)
Then,
We know that
Perimeter of rectangle means sum of all four sides or 2(length + breadth).
So,
⇒ Perimeter of rectangle = 2(length + breadth)
⇒ 40 cm = 2(length + 5)
⇒ 40/2 = length + 5
⇒ 20 = length + 5
⇒ 20 - 5 = length
⇒ length = 15 cm.
Again,
Area of rectangle means the product of its length and its breadth or length *breadth square unit.
⇒ Area of rectangle = length*breadth
⇒ Area of rectangle = 15*5 cm²
⇒ Area of rectangle = 75 cm²
Hence, the area of rectangle is 75 cm².