Math, asked by sachinkumar1747, 11 months ago

Find the area of rectangle whose perimeteris 47m and length is 15m

Answers

Answered by bhavikachopra50
0

hiii,

PERIMETER = 2(L + B) = 47

=> 2(15 + B) = 47

=> 30 + 2B = 47

=> 2B = 47 - 30

=> 2B = 17

=> B = 17/ 2 = 8.5m

AREA = 15 × 8. 5 = 127.5 m^2

{B}Hope it helps you ,pls mark as brainliest answer{/B}......

Answered by omdg
0

Length =15m

Perimeter =2(l+b)=47

=l+b=47/2

=15+b=23.5

=b=23.5-15=8.5m

Area of rectangle = l*b

=15*8.5

=127.5m²

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