Question

Find the area of rectangle whose side are (a) 5 cm and 4 cm (b) 9 cm and 15 cm​

Answer 1

Answer:

$(a)l = 5 \\ \: \: \: \: \: \: b = 4 \\ \: \: a(rectangle) = l \times b \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 5 \times 4 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 \\ (b)l = 15 \\ b = 9 \\ a(rectangle) =l \times b \\ = 9 \times 15 \\ = 135$

mark me as brainlist and also follow me

Answer 2

Answer:

Area -:

(a) 20 cm

(b) 135 cm

Step-by-step explanation:

Given :

Length and Breadth of rectangle -:

(a) 5cm and 4cm

(b) 9cm and 15cm

To find :

The area of the rectangle

Taken :

Formula to find the area of the rectangle -:

$\sf{A=L\:\times\:B}$

Where ,

A = Area of the rectangle

L = Length

B = Breadth

Solution :

(a) -:

$:\implies\sf{A=5cm\times4cm}$

$:\implies\sf{A=20cm}$

(b) -:

$:\implies\sf{A=9cm\times15cm}$

$:\implies\sf{A=135cm}$