Question

Find the area of rectangle with perimeter 168 m and length 34 m​

Answer 1

Answer:

perimeter of rectangle=2(l+b)

168=2(34+b)

84=34+b

b=50

Area of rectangle=l×b

=34×50

=1700m^2

Answer 2

Answer:

The area of rectangle is  $1700$ $m^{2}$.

Step-by-step explanation:

Given : Perimeter of rectangle = $168$ m

          Length of rectangle = $34$ m

To find : Area of rectangle =?

Solution :

• It is given that Perimeter of rectangle = $168$ m

          Length of rectangle = $34$ m

• We have to find the area of rectangle.
• We have a formula,

    Area of rectangle = $l*b$      

• We know that, perimeter of rectangle is the sum of lengths of all four sides of the rectangle.

   Perimeter of rectangle = $2(l+b)$

                         ∴ $168 = 2(34+b)$

                          ∴ $168 = 68+2b$

                          ∴ $2b =168-68$

                          ∴ $2b=100$

                            ∴ $b=\frac{100}{2}$

                            ∴ $b=50$ m

• Now, Area of rectangle = $l*b$

                                   = $34*50$

                                   = $1700$ $m^{2}$

• ∴ The area of rectangle is  $1700$ $m^{2}$.