Question

find the area of rectangle with side 2 5/6cm and 4 4/7cm ​

Answer 1

• Area of rectangle is 12.95 cm².

Step-by-step explanation:

To find:-

• Area of rectangle.

Solution:-

Given that,

• Sides of rectangle are $\sf 2 \cfrac{5}{6}$ cm and $\sf 4 \cfrac{4}{7}$ cm .

We know that,

Area of rectangle = Length × Breadth

Let the length be $\sf 2 \cfrac{5}{6}$ cm.

And Breadth be $\sf 4 \cfrac{4}{7}$ cm .

So,

$\longrightarrow \sf 2 \cfrac{5}{2} \times 4 \cfrac{4}{7}$

$\longrightarrow \sf \cfrac{17}{6} \times \cfrac{32}{7}$

$\longrightarrow \sf \cfrac{544}{42}$

$\longrightarrow \sf 12.95$

Therefore,

Area of rectangle is 12.95 cm².

____________________

More information :-

• Rectangle is a closed figure.
• It's is a quadrilateral.
• It's all angles are of 90°.
• It's opposite sides are equal and parallel.
• It's Perimeter is 4 × Sides.

Answer 2

$\sf \: Length \: of \: rectangle \: = 2 \frac{5}{6} cm$

$\sf \: Breadth \: of \: rectangle \: = 4 \frac{4}{7}$

$\sf \: Therefore,$

$\sf \: Area \: of \: rectangle \: = l × b$

$\sf \implies \: 2\frac{5}{6} \times 4 \frac{4}{7} \\ \\ \sf \implies \: \frac{17}{6} \times \frac{32}{7} \\ \\ \sf \implies \: \frac{544}{42} .....$