Question

Find the area of rectangles with the following pairs of monomials as their length and breadth respectively: (2a², 3ab)​

Answer 1

Answer:

$6a^3b$

Step-by-step explanation:

A = l x b

A = 2a sq x 3ab

A = 2 x a x a x  3 x a x b

A = 2 x 3 x a x a x a x b

A = $6a^3b$

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Answer 2

Step-by-step explanation:

area of the rectangle=length×breadth

$= ( {2a}^{2} )(3ab)$

$a(2a)(3b)$

$a(6ab)$