Math, asked by vaibhavkate077, 4 days ago

Find the area of rectangles with the following pairs of monomials as their length and breadth respectively. (6m2n 2p), (2mnp2 )​

Answers

Answered by pratyushkatkar111
0

Answer:

Step-by-step explanation:

area = l x b = 6m2n2p x 2mnp2

                    = 24mnp x 4 mnp

                    =  96 m^2 n^2 p^2

Answered by preeti353615
1

Answer:

The area of the rectangle is 12 m^3n^3p^3 .

Step-by-step explanation:

Given:

The Length of the rectangle = 6m^2n^2p

And the breadth of the rectangle = 2mnp^2

Find the area of the rectangle.

Formula: the area of the rectangle = length × breadth

Step

The area of the rectangle = length × breadth

= 6m^2n^2p \times 2mnp^2\\= (6 \times 2) m^3n^3p^3\\= 12 m^3n^3p^3

So, the area of the rectangle is 12 m^3n^3p^3 .

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