Question

find the area of rectangular whose length is thrice it's breadth where breadth is 4 x​

Answer 1

Answer:

let at length b l and breadth b b therefore l= 3b , b = 4x, therefore l = 4 x ×3 = 12x area of rectangle=l×b =12x×4x=48x².

Answer 2

$\underline{\bf \red{Correct\;question}} :$

Find the area of rectangle whose length is thrice of its breadth . Where breadth 4

$\underline{\bf \orange{Diagram}} :$

$\setlength{\unitlength}{1mm} \begin{picture}(0,0)\linethickness{01}\put(0,0){\line(3,0){3cm}}\put(0,0){\line(0,2){1.7cm}}\put(30,0){\line(0,4){1.7cm}}\put(0,17){\line(4,0){3cm}}\put(32,7){\bf 4} \put(12,-4){\bf 12}\end{picture}$

$\underline{\bf \green{Solution}} :$

Here , given

• Breadth = 4
• And length is thrice of its breadth

To find ,

• Area = ?

By the given information.

→ 3(breadth) = Length

→ 3(4) = length

→ length = 12

Now , finding area

Area of rectangle = length × Breadth

Area of rectangle = 12 × 4

Area of rectangle = 48

Hence , area of rectangle = 48 units