Find the area of region bounded by the curve x^2+y^2=8x
.
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Answer:
Answer
1+x
2
1
−log(1+x
2
)
y
2
=8x
y=
8x
y=2
2x
area=2
0
∫
2
ydx=2
0
∫
2
2
2
x
dx
=4
2
0
∫
2
x
dx=4
2
[
3/2
x
3/2
]
0
2
=
3
8
2
[2
3/2
−0]=
3
8
2
2
2
=
3
32
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