Find the area of region bounded by x^2=4y,y=2,y=4 and the y-axis in 1st quadrant
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Step-by-step explanation:
Given curve is x2=4y⇒x=2√y. The required area is bounded by the curve $x^2=4y,y=2,y=4 and the y-axis in the first quadrant. Hence A=2∫42√ydy. =32−8√23sq.
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