Question

Find the area of rhombus ABCD whose vertices are taken in order are A(-1, 1) , B(1, -2) , C(3, 1) and D(1, 4) .​

Answer 1

Given

• ABCD is a rhombus whose vertices are in order A(-1, 1) , B(1, -2) , C(3, 1) and D(1, 4) .

To Find

• Area of Rhombus ABCD

Construction

• Locate Point A,B,CA and D On a Graph Page

Solution

From The Above construction we Get,

AC and DB is the Diagonal of Rhombus ABCD

In which

• AC=4cm
• DB=6cm

$\gray{ \sf \: Area \: of \: Rhombus ~ABCD \: = \dfrac{1}{2} d\frac{}{1} \times d\frac{}{2}}$

${\implies\sf \: Area \: of \: Rhombus ~ABCD \: = \dfrac{1}{2} \times4 \times 6}$

$\implies\sf \: Area \: of \: Rhombus ~ABCD \: = \dfrac{24}{2}$

$~~~~\sf \: Area \: of \: Rhombus ~ABCD\: = 12 \: units$

Answer 2

Step-by-step explanation:

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