Find the area of Rhombus ABCD, whose vertices are taken in order are
A (-1,1), B (1, -2), C (3,1) and D (1, 4)
Answers
Answered by
2
Answer:
12
Step-by-step explanation:
The area of rhombus =
where p and q are the diagonals of rhombus
A (-1,1) B ( 1 ,-2 ) C ( 3,1) D(1 , 4 )
The diagonal
AC = = √(3+1)^2+(1-1)^2=4
BD = √(1-1)^2+(4+2)^2 =6
Area = = 6*1/2=12
Similar questions