find the area of rhombus each sides of which measures 20cm and one of whose diagonalas is 24cm
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Other diagonal 2(√20^2 - 12^2)
= 2(√256)
=2×16
=32cm
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Answer:
A = 384cm²
a = Side = 20cm
p = Diagonal = 24 cm
a = pq / 2
a = p² + q² / 2
a = 1 / 2 p √4² - p²
= 1 / 2 • 24 • √ 4.20² - 24² = 384 cm³
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