Find the area of rhombus having each side of length 13 cm and whose diagonal is 10cm
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We know that the diagonal of a rhombus bisect each other at right angles .
ＯＡ = １/２ × ＡＣ = 1０×１/２ = ５ ｃｍ
ａｎｄ ＡＯＢ = ９０° .
ＯＢ = √ＡＢ²－ＯＡ ² = √ 13² - ５² = １２ｃｍ
ＢＤ = (２×ＯＢ) = (２×１２) = ２４ ｃｍ
Ａｒｅａ ｏｆ ｒｈｏｎｂｕｓ ＡＢＣＤ = (１/２×ＡＣ×ＢＤ)
(１/２× 10 × 24 ) = １２０ ｃm² .
Let see one diagram to understand the question .
ＯＡ = １/２ × ＡＣ = 1０×１/２ = ５ ｃｍ
ａｎｄ ＡＯＢ = ９０° .
ＯＢ = √ＡＢ²－ＯＡ ² = √ 13² - ５² = １２ｃｍ
ＢＤ = (２×ＯＢ) = (２×１２) = ２４ ｃｍ
Ａｒｅａ ｏｆ ｒｈｏｎｂｕｓ ＡＢＣＤ = (１/２×ＡＣ×ＢＤ)
(１/２× 10 × 24 ) = １２０ ｃm² .
Let see one diagram to understand the question .
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