Question

find the area of Rhombus having side is equal to 13 cm and one of its diagonals 10 cm​

Answer 1

Answer:

Step-by-step explanation:

diagonal ²= (13/2)²*2

=169/2

area of rhombus =1/2 d₁*d₂

=169/2*10*1/2

=845/2

=422.5 cm² ans

Answer 2

$\huge\text{\underline{\underline{Solution:}}}$


$\text{\underline{\underline{Here,}}}$

$\text{AD=13}$, $\text{OD=5}$, $\text{AO=?}$


$\text{\underline{\underline{According\:to\:the\:Pythagoras\:Theorem,}}}$

$\bold{ {AD}^{2} = {AO}^{2} + {OD}^{2}}$


$\text{\underline{\underline{So,}}}$

$\bold{{13}^{2} \:\:= {AO}^{2} + {5}^{2}}$

$\bold{169 \:\:= {AO}^{2} + 25}$

$\bold{{AO}^{2} = 169 - 25}$

$\bold{{AO}^{2} = 144}$

$\bold{AO \:\:= \sqrt{144}}$

$\bold{AO \:\:= 12 \: cm}$


$\text{\underline{\underline{Now,}}}$

$\bold{AO=12}$


$\text{\underline{\underline{Therefore,}}}$


Area (Rhombus) $\bold{= \frac{1}{2} \times d_{1} \times d_{2}}$

$\bold{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= \frac{1}{2} \times 10 \times 12}$

$\bold{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= \frac{1}{2} \times 120}$

$\bold{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 1 \times 60}$

$\bold{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 60 \: {cm}^{2} }$


$\text{\underline{\underline{NOTE:}}}$

Check this attachment..!!