find the area of rhombus if all sides are 10 cm and one of the diagonal is 12 cm??
Answers
Answered by
5
Answer:
96 cm ^2
Step-by-step explanation:
Let the diagnals be d1, d2.
Given: d1 = 12cm
Since diagonals bisect each other at right angles,
By Pythagoras theorem,
( d1 / 2 ) ^2 + ( d2 / 2 ) ^2 = 10 ^2
( 12 / 2 ) ^2 + ( d2 / 2 ) ^2 = 100
36 + ( d2 / 2 ) ^2 = 100
( d2 / 2 ) ^2 = 64
d2 / 2 = 8
d2 = 16 cm
Area of a rhombus =
( 1 / 2 ) × product of diagonals
= ( 1 / 2 ) × d1 × d2
= ( 1 / 2 ) × 12 × 16
= 96 cm ^2
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Answered by
17
Answer:
hello
Step-by-step explanation:
area of rhombus = 96 cm2
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