Math, asked by vinrana23, 11 months ago

find the area of Rhombus in which each side is equal to 10 cm and one of whose diagonals is 12 CM


sushilkumaragr468: Mark it brainlist please

Answers

Answered by sushilkumaragr468
4

Hey bro

Mark it brainlist please.


Here is the answer you were finding

What is the area of a rhombus on which one side measures 10 cm and the diagonal measures 12 cm?


96


The diagonals in a rhombus are perpendicular , and bisect each other


Given length of side is 10 cm and one diagonal as 12 cm we can find the length of other diagonal


From the above figure let DB be the 12 cm diagonal,now OB and OD are 6 cm


Now consider triangle AOB ,this is a right andled triangle and we know AB=10cm and OB=6cm ,using Pythagoras theorem we can find out lenth of OA as 8cm ,so length of diagonal AC is 2*8=16cm


Area of rhombus is product of diagonal divided by 2, 16*12/2=96


sushilkumaragr468: Please
sushilkumaragr468: (h)2=(b)2+(p)2
sushilkumaragr468: As hypotenuse is greater than and equal to the sum of perpendicular and base
sushilkumaragr468: Now mark it brainlist please
Answered by YOURDAAMAN
2
HEY MATE HERE I AM TELLING YOU THE CORRECT ANSWER BUT I CAN GIVE YOU THE HINT...BECAUSE IN EXAMS NO ONE CAN GIVE YOU WHOLE SOLUTION...

SO THE HINT IS USE PYTHAGORAS THEOREM...
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