Math, asked by sonipriya1161, 8 months ago

find the area of Rhombus in which each side is equal to 25 cm and one of its diagonal is 40 cm ​

Answers

Answered by Sanskriti141
3

Answer:

600 cm²

Step-by-step explanation:

GIVEN THAT :

Length of each side of a rhombus = 25 cm

Length of one of the diagonals = 40 cm

Let the other diagonal be x cm

We know,

Diagonals of a rhombus bisect each other at right angles.

Therefore,

According to the figure in the attachment,

=> AB² = OA² + OB²

=> ( 25 )² = ( 20 )² + OB²

=> OB² = 625 - 400

=> OB² = 225

=> OB = √225

=> OB = 15 cm

=> OB = 15 cmSo, BD = 30 cm

Area of rhombus =

=> 1/2 × D1 × D2

=> 1/2 × D1 × D2where, D1 and D2 are the two diagonals of the rhombus

=> 1/2 × AC × BD

=> 1/2 × 40 × 30

=> 20 × 30

=> 600 cm²

ANS) Area of the rhombus is 600 cm²

Thanks !

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