Find the area of rhombus in which perimeter is 400m and one of its diogonal is 160m
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perimeter is 100 m means that side is 100 m.
we know both diagonal are perpendicular bisector. so half of 160 is 80 . Draw the diagram and you will find a triangle of hypotenuse 100 m and one of the side 80 m.
use pythagoras theorem and you will get other side as 60 m. that means other diagonal is 120 m. Area of rhombus is( 1/2 *d1* d2 ).
so put the values 1/2 * 160 * 120
We get the answer 9600 m²
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