Find the area of rhombus is each side of which measures 20cm and one of whise diagonal s is 24cmv
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side of rhombus = 20 cm
therefore hypotenuse = 20 cm
one side = 24/2 = 12 cm
let the other side be X
x




area of rhombus = 1/2 d1d2
= 1/2×24×32 = 384 cm2
therefore hypotenuse = 20 cm
one side = 24/2 = 12 cm
let the other side be X
x
area of rhombus = 1/2 d1d2
= 1/2×24×32 = 384 cm2
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