Question

find the area of rhombus is side of which is equal to 15 cm and one of whose diagonal is 24 cm

Answer 1

Let ABCD is a rhombus with diagonals AC and BD which intersect each other at O.

AC = 24 ⇒ AO = 12

Let BO = x and AB = 15 cm (given)
By Pythagorean theorem
c2 = a2 + b2
225 = 144 + x²
x2 = 225 – 144
x2 = 81
x = 9 cm
BO = 9 cm

Diagonal BD = 2 x 9= 18cm.

Area = ½ x [ product of diagonals]
= ½ x 24 x 18

Area = 216sq.cm

I hope it is helped you

Answer 2

What do you mean please write it clearly