Question

find the area of Rhombus its diagonals measure 8 cm and its side is 5cm​

Answer 1

Answer:

24cm^2

Step-by-step explanation:

let d1 = 8 cm

length of other diagonal d2

by Pythagoras theorem,

= 2 × √(5^2 - (d1/2)^2]

=2× √(5^2 - 4^2) = 2×3 = 6cm

area of rhombus = d1 × d2/2

= 8 × 6/2 = 24cm^2 Answer

Answer 2

Answer:

Step-by-step explanation:

The diagonals of the rhombus are perpendicular and bisect each other. Therefore, the diagonal of 8 cm is divided into two segments 4 cm long. Using the Pythagorean Theorem and any of the right triangles to solve for x.

5^2=4^2+x^2

x^2=25−16

x^2=9

x=3

One the formulas for the area of a rhombus is A=12d1d2

d1=8cm

d2=6cm

A=12(8)(6)=24

A = 24 cm^2